Question

<xsl:value-of select="substring-before($temp1,';')" disable-output-escaping="yes"/>

where temp1="fassdf sdf; asdf &dfsdfsdf;fsdfsf;"

The above code I am using to split value using “;”. The problem is temp1 having &, so it splits this value by the escaped sequence character ;. So i am getting wrong output. But if I use the disable-output-escaping="yes" then the "&" is converted to &.

How to get the formatted value from the string? So if i split the string i will not get any issue. Because I will get string with & instead of &

Answer 1

Lets assume a sample XML for your/our convenience ..

<?xml version="1.0" encoding="utf-8"?>
<root>
  <child>sharepoint; R&amp;D;Department;</child>
</root>

XSLT code to output the desired one:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
  <xsl:output method="text" indent="no"/>
  <xsl:strip-space elements="*"/>

  <xsl:template match="/">
    <xsl:apply-templates select="node()"/>
  </xsl:template>

  <xsl:template match="child">
    <xsl:call-template name="SplitString">
      <xsl:with-param name="StringVal" select="concat(.,';')"/>
    </xsl:call-template>
  </xsl:template>

  <xsl:template name="SplitString">
    <xsl:param name="StringVal"/>
    <xsl:variable name="first" select="substring-before($StringVal, ';')" />
    <xsl:variable name="remaining" select="substring-after($StringVal, ';')" />

    <xsl:value-of select="normalize-space($first)" disable-output-escaping="yes" />

    <xsl:if test="$remaining">
      <xsl:value-of select="'&#10;'"/>
      <xsl:call-template name="SplitString">
        <xsl:with-param name="StringVal" select="$remaining" />
      </xsl:call-template>

    </xsl:if>
  </xsl:template>

</xsl:stylesheet>

This is the Output you get:

sharepoint
R&D
Department