$y = 013;
echo $y + 5; //this result in 16
I can not figure it out how its ans is 16? Can any one help?
$y = 013; echo $y + 5; //this result in 16 I can not
Share
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
$y = 013;
echo $y + 5; //this result in 16
I can not figure it out how its ans is 16? Can any one help?
because 013 isn’t decimal (base 10). it’s octal (base 8). the value in decimal is:
(0 * 8^2) + (1 * 8^1) + (3 * 8^0) = 0 + 8 + 3 = 11
which gives the correct (though unexpected, at least by you) result of 16 when added to 5.
moral of the story: don’t prepend a number literal with 0 unless you know what it means