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Home/ Questions/Q 8870331
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T17:41:52+00:00 2026-06-14T17:41:52+00:00

Yes, another Java Date post :) My problem: simple standard code, used for test

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Yes, another Java Date post 🙂

My problem:

simple standard code, used for test if an inserted date is in the requested form (dd/MM/yyyy):

SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
try {

   sdf.parse(strDate); 

} catch(ParseException e) {

   // err

}

strDate = “10-12-2012” —-> sysout = err (ok)

strDate = “2012-11-10” —-> sysout = err (ok)

strDate = “15/10/2011” —-> sysout = parse (ok)

the problem:

strDate = “2012/12/15” —-> sysout = this date that i expect an error
result parsed like “Tue Jun 03 00:00:00 CET 21”

Who knows???

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T17:41:54+00:00Added an answer on June 14, 2026 at 5:41 pm

    just set setLenient to false.

    FROM API :

    setLenient method:

    Specify whether or not date/time parsing is to be lenient. With
    lenient parsing, the parser may use heuristics to interpret inputs
    that do not precisely match this object’s format. With strict parsing,
    inputs must match this object’s format.

    SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy");
    try {
      sdf.setLenient(false);
      System.out.println(sdf.parse("2012/12/15")); 
    } catch(ParseException e) {
      e.printStackTrace();
    }
    
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