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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:55:56+00:00 2026-05-13T14:55:56+00:00

Yes, I know this subject has been covered before: Python idiom to chain (flatten)

  • 0

Yes, I know this subject has been covered before:

  • Python idiom to chain (flatten) an infinite iterable of finite iterables?
  • Flattening a shallow list in Python
  • Comprehension for flattening a sequence of sequences?
  • How do I make a flat list out of a list of lists?

but as far as I know, all solutions, except for one, fail on a list like [[[1, 2, 3], [4, 5]], 6], where the desired output is [1, 2, 3, 4, 5, 6] (or perhaps even better, an iterator).

The only solution I saw that works for an arbitrary nesting is found in this question:

def flatten(x):
    result = []
    for el in x:
        if hasattr(el, "__iter__") and not isinstance(el, basestring):
            result.extend(flatten(el))
        else:
            result.append(el)
    return result

Is this the best approach? Did I overlook something? Any problems?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T14:55:56+00:00Added an answer on May 13, 2026 at 2:55 pm

    Using generator functions can make your example easier to read and improve performance.

    Python 2

    Using the Iterable ABC added in 2.6:

    from collections import Iterable
    
    def flatten(xs):
        for x in xs:
            if isinstance(x, Iterable) and not isinstance(x, basestring):
                for item in flatten(x):
                    yield item
            else:
                yield x
    

    Python 3

    In Python 3, basestring is no more, but the tuple (str, bytes) gives the same effect. Also, the yield from operator returns an item from a generator one at a time.

    from collections.abc import Iterable
    
    def flatten(xs):
        for x in xs:
            if isinstance(x, Iterable) and not isinstance(x, (str, bytes)):
                yield from flatten(x)
            else:
                yield x
    
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