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Home/ Questions/Q 6214017
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T06:48:09+00:00 2026-05-24T06:48:09+00:00

Yesterday I made a small script with some help to read .csv files. I

  • 0

Yesterday I made a small script with some help to read .csv files. I though I found a way to read the first value and store it, but for some reason it stores the last value instead.

I store what I thought should be the first value under value1, and re-display it to make sure it displays properly and is in fact being stored under a callable variable.

Does anyone know what is wrong with this code? I think I should be using vectors but as I read the reference sheets I find on the internet about them I am being a little thrown of. Any help is appreciated.

#include <iostream>
#include <fstream>
#include <string>

using namespace std;

int main ()
{

    int loop = 1;
    string value;
    string value1;

    while(loop = 1)
    {

        cout << "Welcome! \n" << endl;

        ifstream myfile;

        myfile.open ("C:/Documents and Settings/RHatfield/My Documents/C++/Product Catalog Creator/Source/External/Sample.csv");

        while (myfile.good())

        getline ( myfile, value, ',' );
        cout << string ( value) << endl; 

        value1 = value;

        cout << value1;

        myfile.close();

        system("PAUSE");

        return 0;
    }


}
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  1. Editorial Team
    Editorial Team
    2026-05-24T06:48:10+00:00Added an answer on May 24, 2026 at 6:48 am

    Your error seems to be in pure code formatting.

    while (myfile.good())
    

    There is no {} after the loop. So only next line is repeated.

    The following code is executed after reading of the whole file.

    cout << string ( value) << endl;
    

    Thus value stores the last line of the file.

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