Question

Yesterday I was too tired to post correct and specific question. So there it is:

if (t==2){
    printf ("abc\n");
    printf ("abc = "); scanf ("%f",&r);
    printf ("abc = "); scanf ("%d",&n);
    printf ("abc = "); scanf ("%d",&k);
    a=2*r;
    b=2*r;
    c=2*r;

    for (i=0;i<=n;i++){
        float x=(float)rand()/((float)RAND_MAX/a);
        float y=(float)rand()/((float)RAND_MAX/b);
        float z=(float)rand()/((float)RAND_MAX/c);

        if ((x-(r))*(x-(r))+(y-(r))*(y-(r))+(z-(r))*(z-(r))<=(r*r))
            m++;

            if ( i % k ==0 && i > 0 ){
                freopen ( "data.txt","w", stdout );
                printf("%s %s      %s \n","#","n","Vka");
                Vka = ( 2*r*2*r*2*r )*m/i;
                printf("% 6.2f % 6.2f \n",n,Vka);
                fclose (stdout);
            }

    }

    Vk=(2*r*2*r*2*r)*m/n;
    printf ("abc =%d\n", m);
    printf ("abc=%d\n", n);
    printf("abc =%f", Vk);

    }

Unfortunately program does not work as I want it to work. It should export the data to the file “data.txt”, but the file still looks like this:

# n      Vka 
0.00   0.00 

Morover the program finishes operation just after creating this file, while I want it to finish its operation on printing Vk in the terminal.

Answer 1

1. open the file before the loop
2. write to the file inside the loop using fprintf
3. close the file after the loop

There’s no reason in this program to mess with stdout at all.