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Home/ Questions/Q 7810455
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T03:47:17+00:00 2026-06-02T03:47:17+00:00

Yo. I have this extremely simple swap function that seems to not work. Probably

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Yo. I have this extremely simple swap function that seems to not work. Probably a pointer issue so any advice would be nice.

void swap(pQueue *h, int index1, int index2) {
  student *temp = &h->heaparray[index1];
  h->heaparray[index1] = h->heaparray[index2];
  h->heaparray[index2] = *temp;    
}

pQueue is a heap pointer, index1 and index2 are guaranteed to be valid indices.

student *temp does get the value of heaparray[index1] but when heaparray[index2] is assigned the temp value, the heaparray[index2] stays the same. Any advice appreciated.

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  1. Editorial Team
    Editorial Team
    2026-06-02T03:47:19+00:00Added an answer on June 2, 2026 at 3:47 am

    You need to copy the actual value of h->heaparray[index1] (not its address) into temp and then later copy that value into h->heaparray[index2], like so:

    void swap(pQueue *h, int index1, int index2) {
      student temp = h->heaparray[index1];
      h->heaparray[index1] = h->heaparray[index2];
      h->heaparray[index2] = temp;    
    }
    
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