You are given an array of elements. Some/all of them are duplicates. Find them in 0(n) time and 0(1) space. Property of inputs – Number are in the range of 1..n where n is the limit of the array.
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You are given an array of elements. Some/all of them are duplicates. Find them in 0(n) time and 0(1) space. Property of inputs – Number are in the range of 1..n where n is the limit of the array.
If the O(1) storage is a limitation on additional memory, and not an indication that you can’t modify the input array, then you can do it by sorting while iterating over the elements: move each misplaced element to its “correct” place – if it’s already occupied by the correct number then print it as a duplicate, otherwise take the “incorrect” existing content and place it correctly before continuing the iteration. This may in turn require correcting other elements to make space, but there’s a stack of at most 1 and the total number of correction steps is limited to N, added to the N-step iteration you get 2N which is still O(N).