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Home/ Questions/Q 6674489
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T03:45:07+00:00 2026-05-26T03:45:07+00:00

zip_file_name = not_exist.py try: with zipfile.ZipFile(zip_file_name) as f_handle: print(open it successfully) except (zipfile.BadZipfile, zipfile.LargeZipFile),

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zip_file_name = "not_exist.py"

try:
   with zipfile.ZipFile(zip_file_name) as f_handle:
       print("open it successfully")
except (zipfile.BadZipfile, zipfile.LargeZipFile), e:
       print(e)

Is this the correct way to handle exception throw by a with statement?

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  1. Editorial Team
    Editorial Team
    2026-05-26T03:45:08+00:00Added an answer on May 26, 2026 at 3:45 am

    Yes, this is how you would want to handle exceptions from inside a with statement. ContextManagers (that implement the behavior behind the with statement) can handle exceptions but should only do so to properly clean up resources used by the object.

    Here’s a snippet from the relevant documentation:

    If BLOCK raises an exception, the context manager’s exit() method
    is called with three arguments, the exception details (type, value,
    traceback, the same values returned by sys.exc_info(), which can also
    be None if no exception occurred). The method’s return value controls
    whether an exception is re-raised: any false value re-raises the
    exception, and True will result in suppressing it. You’ll only rarely
    want to suppress the exception, because if you do the author of the
    code containing the ‘with‘ statement will never realize anything went
    wrong.

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