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Home/ Questions/Q 4022534
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T10:29:14+00:00 2026-05-20T10:29:14+00:00

Zip::ZipOutputStream.open(folderpath) do |z| z.print IO.read(folderpath) In the code above, I have Zip::ZipOutputStream.open(file_path) do |z|

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    Zip::ZipOutputStream.open(folderpath) do |z|
        z.print IO.read(folderpath)

In the code above, I have Zip::ZipOutputStream.open(file_path) do |z|. I do not understand, what the do |z| mean? What does |z| refer to? Can I for example change |z| to other, example is |changez| ?

I got the complete code here
http://blog.devinterface.com/2010/02/create-zip-files-on-the-fly/ but I can not undestand the 1st line of do |z| .

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  1. Editorial Team
    Editorial Team
    2026-05-20T10:29:14+00:00Added an answer on May 20, 2026 at 10:29 am

    whatever comes inside ||, considered to be the parameters for the anonymous method (or lambda expression) that comes next,

    for ex:

      (1..3).each do |n|
           puts n
      end
    

    can be rewritten as

      (1..3).each {|n| puts n}
    

    |n| could be anything, just a name for a variable.

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