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Asked: 2026-05-12T05:20:06+00:00

A) (Int32)X | ((Int32)Y << 16) ; B) (Int32)X + (Int32)Y * (Int32)Int16.MaxValue ;

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A) (Int32)X | ((Int32)Y << 16);

B) (Int32)X + (Int32)Y * (Int32)Int16.MaxValue;

Shouldn’t both be equivalent? I know from testing that the first works as expected, but for some reason the second doesn’t. Both X and Y are shorts (Int16), and the return type is an integer (Int32).

Shouldn’t Y << 16 <=> Y * Int16.MaxValue?

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1 Answer

  1. Editorial Team

    To get the desired behaviour, you need to multiply with 0x10000 (i.e. UInt16.MaxValue+1). Int16.MaxValue is 0x7fff.

    5 << 16
327680

5 * 0x10000
327680

    Compare to the decimal system: If you want to “shift” the number 5 to 500, you need to multiply with 100, not 99 🙂

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