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Home/ Questions/Q 613061
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T17:57:40+00:00 2026-05-13T17:57:40+00:00

A LinkedList can’t be serialized using XmlSerializer. Now, how to however save/retrieve data from

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A LinkedList can’t be serialized using XmlSerializer.

Now, how to however save/retrieve data from a serialized objet LinkedList. Should I implement custom serialization?

What I tried to do:

using System.Xml.Serialization;

[Serializable()]
public class TestClass
{
    private int _Id;
    private string _Name;
    private int _Age;
    private LinkedList<int> _linkedList = new LinkedList<int>();

    public string Name {
        get { return _Name; }
        set { _Name = value; }
    }
    
    public string Age {
        get { return _Age; }
        set { _Age = value; }
    }
    
    [XmlArray()]
    public List<int> MyLinkedList {
        get { return new List<int>(_linkedList); }
        set { _linkedList = new LinkedList<int>(value); }
    }
}

What I’ve obtained(addind name, age and some items in the mylinkedlist):

<?xml version="1.0"?>
<TestClass 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Name>testName</Name>
  <Age>10</Age>
  <MyLinkedList />
</TestClass>

So, the items in the linked list hadn’t been serialized… 🙁

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T17:57:41+00:00Added an answer on May 13, 2026 at 5:57 pm

    One possibility would be the creation of a serializable collection that contains the same objects as the linked list. E.g. (untested):

    LinkedList<Foo> ll = PopulateLinkedList();
    List<Foo> list = new List<Foo>(ll);
    

    Then serialize list instead. This isn’t going to create a lot of overhead if Foo is a reference type, and you don’t care about the fact that insertions/deletions are now more expensive b/c you’re only using the List<T> to hold references to the data for serialization and deserialization purposes. When you pull it out of the serialized stream, you can just turn it back into a LinkedList<T> to get all those advantages you were using a linked list for in the first place.


    Here’s a little console app I just whipped up to demonstrate. I did it in VS2008, but I don’t think I used anything surprising– just the array initialization syntax to save some vertical space.

    Sample Code:

    [Serializable]
    public class MyClass
    {
        private string name;
        private int age;
        private LinkedList<int> linkedList = new LinkedList<int>();
    
        public string Name
        {
            get { return name; }
            set { name = value; }
        }
    
        public int Age
        {
            get { return age; }
            set { age = value; }
        }
    
        [XmlArray]
        public List<int> MyLinkedList
        {
            get { return new List<int>(linkedList); }
            set { linkedList = new LinkedList<int>(value); }
        }
    }
    

    And the main application code:

    class Program
    {
        static void Main(string[] args)
        {
            MyClass c = new MyClass();
    
            c.Age = 42;
            c.Name = "MyName";
            c.MyLinkedList = new List<int>() { 1, 4, 9 }; // Your property impl requires this be set all at once, not one element at a time via the property.
    
            XmlSerializer s = new XmlSerializer(typeof(MyClass));
            StringWriter outStream = new StringWriter();
            s.Serialize(outStream, c);
    
            Console.Write(outStream.ToString());
    
            return;
        }
    }
    

    This kicks the following out to the console:

    <?xml version="1.0" encoding="utf-16"?>
    <MyClass xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
      <Name>MyName</Name>
      <Age>42</Age>
      <MyLinkedList>
        <int>1</int>
        <int>4</int>
        <int>9</int>
      </MyLinkedList>
    </MyClass>
    
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