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Home/ Questions/Q 6346681
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T21:03:58+00:00 2026-05-24T21:03:58+00:00

$a = true; $b = true; if (($a == false) || ($b == false))

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$a = true;
$b = true;


if (($a == false) || ($b == false)) {
 echo "BAD";
} else {
  echo "OK";
}

why this show me “BAD”? how can i fix it?

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  1. Editorial Team
    Editorial Team
    2026-05-24T21:03:58+00:00Added an answer on May 24, 2026 at 9:03 pm

    The code will not echo BAD because the expression evaluates to false, yielding OK:

    ($a == false) || ($b == false)
    ↓
    (true == false) || (true == false)
    ↓
    false || false
    ↓
    false
    

    (Demo)

    Some other error must exist.

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