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Editorial Team
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Asked: 2026-06-17T09:33:51+00:00

After loading an assembly, when instantiating it: Assembly asm = Assembly.LoadFile(@c:\file.dll); Type type =

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After loading an assembly, when instantiating it: 

Assembly asm = Assembly.LoadFile(@"c:\file.dll");
Type type = asm.GetType("DLLTYPE");
object instance = Activator.CreateInstance(type);

How C# know the type?
From my logic, the dll should have header which define the object type.
so why is the DLLTYPE string for ?

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1 Answer

  1. Editorial Team

    How C# know the type?

    You’ve passed it as parameter:

    Type type = asm.GetType("DLLTYPE");

    so why is the “DLLTYPE” string for ?

    It’s the namespace and the class name that you want to instantiate:

    Namespace.ClassName

    Be careful because this method will return null if you make a mistake in the typename. If you want to ensure that the type exists you could use the following overload:

    Type type = asm.GetType("Namespace.ClassName", true);

    This will throw an exception instead of returning null which will be easier to debug instead of the NRE you would otherwise get on the Activator.CreateInstance method.

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