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Home/ Questions/Q 6834397
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T23:06:24+00:00 2026-05-26T23:06:24+00:00

ANSWER : The fix for this problem is this : Change selector from $(‘#Button3’)

  • 0

ANSWER: The fix for this problem is this :

Change selector from $('#Button3') to $('#<%= Button3.ClientID %>')

Thanks to Yuri.

ISSUE:

I am trying to get a button click to run the JQuery BlockUI plugin. I am having some issues this is my first shot at JQuery. I do have the Hello World pop-up example working so I think I am close but could use some help getting the rest worked out.

Here is the code…

<script src="../../scripts/jquery-1.2.6.js" type="text/javascript"></script>
<script src="../../scripts/jquery.blockUI.js" type="text/javascript"></script>

<script type="text/javascript">
 $(document).ready(function() {
     $("#Button3").click(function() {
     $.blockUI();

     setTimeout(function() {
         $.unblockUI({
             onUnblock: function() { alert('onUnblock'); }
         });
     }, 2000);
   });
});

</script>

I am trying to run this on an aspx page. As stated the Hello World popup works but not the blockUI.

Any help would be appreciated.

Here is the button aspx…

 <td>
      <asp:Button ID="Button3" runat="server" Text="Button" />
  </td>

no code behind events on the button.

This apsx page has a Master Page as well.

Some tweaks to the code have prodcued this error when closing the page in Visual Studio…

Microsoft JScript runtime error: Sys.ArgumentTypeException: Object of
type ‘Sys._Application’ cannot be converted to type
‘Sys._Application’. Parameter name: instance

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T23:06:25+00:00Added an answer on May 26, 2026 at 11:06 pm

    First you have to block the UI. then only will it be unblocked. You cannot unblocked something that is not blocked as unblocked == not blocked.

    So uncomment the first line inside the button click event of your code.

    Demo: http://jsfiddle.net/naveen/D9GCj/1/

    Please note that asp:Button will be rendered as input type="submit"

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