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Home/ Questions/Q 415265
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T18:21:50+00:00 2026-05-12T18:21:50+00:00

Anyone can declare ones own operators in C…. that is if one is a

  • 0

Anyone can “declare” ones own operators in C…. that is if one is a C compiler guru and has the source code to the C compiler! 😉

Further questions to puzzle:

  1. How are these operations done in
    C99? gcc? …
  2. And why were /\ & \/ dropped?
  3. Which types were the /\ and \/ operators valid for?

Googling for “/\ \/” naturally returns nothing. Wikipedia has a page for neither /\ nor \/. But I have spotted form similar operators are built into the XML character entities!


Source added: I found the offending example in the PDP’s cc source file “c00.c”:

/*
 * Return the next symbol from the input.
 * peeksym is a pushed-back symbol, peekc is a pushed-back
 * character (after peeksym).
 * mosflg means that the next symbol, if an identifier,
 * is a member of structure or a structure tag or an enum tag
 */
symbol()
{
...
 case BSLASH:
  if (subseq('/', 0, 1))
   return(MAX);
  goto unkn;

 case DIVIDE:
  if (subseq('\\', 0, 1))
   return(MIN);
  if (subseq('*',1,0))
   return(DIVIDE);
...
}

Actual Implementations:
The /\ and \/ operators date back as far as Sixth Edition Unix 1975 (so far). Examples: Unix V6(1975), Unix V7(1979) and more currently BSD 2.11(1992-2008)

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T18:21:51+00:00Added an answer on May 12, 2026 at 6:21 pm

    \/ looks like sup and /\ looks like inf. They could also be ∨ and
    ∧, respectively.

    I don’t remember ever seeing these in K&R 2nd edition or any other C book.

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