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Home/ Questions/Q 3783948
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T11:18:09+00:00 2026-05-19T11:18:09+00:00

As per C precedence tables, the ternary conditional operator has right-to-left associativity. So, is

  • 0

As per C precedence tables, the ternary conditional operator has right-to-left
associativity.

So, is it directly convertible to the equivalent if-else ladder?

For example, can:

x?y?z:u:v;

be interpreted as:

if(x)
{
   if(y)
   { z; }
   else
   { u; }
}
else
{ v; }

by matching an else (:) with the closest unpaired if (?)? Or does right-to-left associativity imply some other arrangement?

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  1. Editorial Team
    Editorial Team
    2026-05-19T11:18:09+00:00Added an answer on May 19, 2026 at 11:18 am

    The example you gave could only be interpreted in one way (like the if statements you gave), whether the ternary operator had right-to-left or left-to-right associativity.

    Where the right-to-left associativity matters is when you have:

    x = a ? b : c ? d : e;
    

    Which is interpreted as: x = a ? b : (c ? d : e), not as x = (a ? b : c) ? d : e.

    To give a more realistic example:

    int getSign(int x) {
        return x < 0 ? -1 :
               x > 0 ?  1 :
                        0;
    }
    

    This is identical to the (probably more readable) if / else-if statements:

    int getSign(int x) {
        if (x < 0)
             return -1;
        else if (x > 0)
             return 1;
        else return 0;
    }
    
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