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Home/ Questions/Q 7688655
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T19:58:18+00:00 2026-05-31T19:58:18+00:00

As the title suggest, I would like to do the above. Example below: library(stringr)

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As the title suggest, I would like to do the above. Example below:

library(stringr)
library(XLConnect)

df <- data.frame(do.call("rbind", lapply(1:10, function(i) rnorm(10))))
df.list <- rep(list(df), 10)
names(df.list) <- paste("DataFrame", str_pad(1:length(df.list), 2, pad = "0"), sep = "")

df.list.workbook <- loadWorkbook("df.list.workbook.xlsx", create = TRUE)
lapply(1:length(df.list), function(i) createSheet(df.list.workbook, name = names(df.list[i])))
lapply(df.list[1:length(df.list)], function(i) writeWorksheet(df.list.workbook, i, sheet = names(i)))

The last line is where it throws up an error:

Error: IllegalArgumentException (Java): Sheet index (-1) is out of range (0..9)

To troubleshoot this, I tried:

lapply(df.list[1:length(df.list)], function(i) print(names(i)))

And realise that the names of the columns were being passed to the sheet variable. Any ideas how to overcome this?

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  1. Editorial Team
    Editorial Team
    2026-05-31T19:58:20+00:00Added an answer on May 31, 2026 at 7:58 pm

    You need to lapply over the index instead of the list:

    lapply(seq_along(df.list), function(i) writeWorksheet(df.list.workbook, df.list[[i]], sheet = names(df.list)[i]))
    
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