Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7035379
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T01:17:51+00:00 2026-05-28T01:17:51+00:00

Assume filteredArray={ 0,2,3,4}. I have another array called tempArray. I want to insert 1

  • 0

Assume filteredArray={ 0,2,3,4}. I have another array called tempArray. I want to insert 1 at zeroth,second,third,fourth position in tempArray.
This code snippet is not working. Any help would be appreciated.

NSMutableArray *tempArray =[[NSMutableArray alloc]init]; 
// Assume filteredArray={ 0,2,3,4}
for (int i=0 ; i<[filteredArray count] ; i++)
{
    [tempArray insertObject:@"1" atIndex:[filteredArray objectAtIndex:i]];
}
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-28T01:17:51+00:00Added an answer on May 28, 2026 at 1:17 am

    to insert objet to array at index, you must have some ojects (not less then index) in array. In different words, you can’t add object at index 5 to array with count 3.
    here is solution i advice:

     for(int i=0;i<[filteredArray count];i++) { 
    [if ([[filteredArray objectAtIndex:i] intValue] == i) [tempArray addObject:@"1"];
    else [tempArray addObject:/*any ampty object*/];
     } 
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have an Array of MKAnnotation objects called arrAnnotations . I want to pick
Assume that we have N erlang nodes, running same application. I want to share
Assume I have a class like this: public class Server { public static void
Assume I have a code like this: @autoreleasepool { for(int i = 0; i
Assume I have an array $arr. It's possible that it has an element with
Assume I have a class like this: public class Foo { public Bar RequiredProperty
Assume I have this barebones structure: project/ main.py providers/ __init.py__ acme1.py acme2.py acme3.py acme4.py
Assume I have a list of words, and I want to find the number
Assume we have an action and we want limited on the number of access
Assume that I have an appstore. developers submit their application in this store. My

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.