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Home/ Questions/Q 8959461
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T15:26:39+00:00 2026-06-15T15:26:39+00:00

Assume that we have the following struct definition that uses generics: public struct Foo<T>

  • 0

Assume that we have the following struct definition that uses generics:

public struct Foo<T>
{
    public T First; 
    public T Second;

    public Foo(T first)
    {
        this.First = first;
    }

}

The compiler says

‘Foo.Second’ must be fully assigned before control is returned to the caller

However, if Foo is a class, then it compiles successfully.

public class Foo<T>
{
    public T First; 
    public T Second;

    public Foo(T first)
    {
        this.First = first;
    }

}

Why? Why the compiler treats them differently? Moreover if no constructor is defined in the first Foo then it compiles. Why this behaviour?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T15:26:41+00:00Added an answer on June 15, 2026 at 3:26 pm

    That is because a compiler rule enforces that all fields in a struct must be assigned before control leaves any constructor.

    You can get your code working by doing this:

    public Foo(T first)
    {
        this.First = first;
        this.Second = default(T);
    }
    

    Also see Why Must I Initialize All Fields in my C# struct with a Non-Default Constructor?

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