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Asked: May 11, 20262026-05-11T02:31:45+00:00 2026-05-11T02:31:45+00:00

Assuming a series of points in 2d space that do not self-intersect, what is

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Assuming a series of points in 2d space that do not self-intersect, what is an efficient method of determining the area of the resulting polygon?

As a side note, this is not homework and I am not looking for code. I am looking for a description I can use to implement my own method. I have my ideas about pulling a sequence of triangles from the list of points, but I know there are a bunch of edge cases regarding convex and concave polygons that I probably won’t catch.

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  1. 2026-05-11T02:31:45+00:00Added an answer on May 11, 2026 at 2:31 am

    Here is the standard method, AFAIK. Basically sum the cross products around each vertex. Much simpler than triangulation.

    Python code, given a polygon represented as a list of (x,y) vertex coordinates, implicitly wrapping around from the last vertex to the first:

    def area(p):     return 0.5 * abs(sum(x0*y1 - x1*y0                          for ((x0, y0), (x1, y1)) in segments(p)))  def segments(p):     return zip(p, p[1:] + [p[0]]) 

    David Lehavi comments: It is worth mentioning why this algorithm works: It is an application of Green’s theorem for the functions −y and x; exactly in the way a planimeter works. More specifically:

    Formula above =
    integral_over_perimeter(-y dx + x dy) =
    integral_over_area((-(-dy)/dy+dx/dx) dy dx) =
    2 Area

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