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Home/ Questions/Q 9237323
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T07:30:38+00:00 2026-06-18T07:30:38+00:00

Assuming I have a struct typedef struct { unsigned char mem1; unsigned char *mem2

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Assuming I have a struct

typedef struct  
{ 
   unsigned char mem1; 
   unsigned char *mem2
} MEMBERS;

where

 unsigned sample = 12
 MEMBERS memvalues = {  0x15 , &sample  };

I need to access both values mem1 and mem2, when a function “GET_MEM” returns the address of the structure “MEMBERS” to X_mem. What I mean is this:

unsigned char *X_mem = GET_MEM ( );    //function returns address of memvalues
unsigned value1 = *X-mem;
unsigned Value2 = *++X_mem;

I want value1 to give 0x15, and value2 gives 12.

How can I make this work?

NOTE: Please do not assume the above code example to be syntactically correct. Its just to express my intention.
Thanks Folks.

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  1. Editorial Team
    Editorial Team
    2026-06-18T07:30:39+00:00Added an answer on June 18, 2026 at 7:30 am

    You need to cast the incorrectly typed pointer returned by GET_MEM():

    const MEMBERS *some_members = (MEMBERS *) GET_MEM();
    unsigned value1 = some_members->mem1;
    unsigned value2 = *some_members->mem2;
    
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