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Home/ Questions/Q 6972477
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T16:58:22+00:00 2026-05-27T16:58:22+00:00

Assuming short is 2 bytes and int is 4 bytes on a 32 bit

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Assuming short is 2 bytes and int is 4 bytes on a 32 bit OS. Is the following an undefined behavior?

short s = 42;
int *p = (int*)(&s);
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  1. Editorial Team
    Editorial Team
    2026-05-27T16:58:23+00:00Added an answer on May 27, 2026 at 4:58 pm

    No, the code that you have posted does not exhibit undefined behavior but attempting to read *p would. Also, depending on the alignment requirements of int and short, the result of the cast may be unspecified and irreversable (see 5.2.10 [expr.reinterpret.cast] / 7).

    See ISO/IEC 14882:2011 3.10 [basic.lval] / 10:

    If a program attempts to access the stored value of an object through a glvalue of other than one of the following types the behavior is undefined:

    • the dynamic type of the object,
    • a cv-qualified version of the dynamic type of the object,
    • a type similar (as defined in 4.4) to the dynamic type of the object,
    • a type that is the signed or unsigned type corresponding to the dynamic type of the object,
    • a type that is the signed or unsigned type corresponding to a cv-qualified version of the dynamic type of the object,
    • an aggregate or union type that includes one of the aforementioned types among its elements or non-static data members (including, recursively, an element or non-static data member of a subaggregate or contained union),
    • a type that is a (possibly cv-qualified) base class type of the dynamic type of the object,
    • a char or unsigned char type.

    The object that you are trying to access is a short and *p is a glvalue of type int which doesn’t meet any of the above descriptions.

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