Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 295117
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 12, 20262026-05-12T06:25:45+00:00 2026-05-12T06:25:45+00:00

I have a 16 bit luminance value stored in two bytes, and I want

  • 0

I have a 16 bit luminance value stored in two bytes, and I want to convert that to R, G, and B values. I have two questions: how do I convert those two bytes to a short, and assuming that the hue and saturation is 0, how do I turn that short into 8 bits per component RGB values?

(The Convert class doesn’t have an option to take two bytes and output a short.)

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-12T06:25:45+00:00Added an answer on May 12, 2026 at 6:25 am

    If the 16 bit value is little endian and unsigned, the 2nd byte would be the one you want to repeat 3x to create the RGB value, and you’d drop the other byte. Or if want the RGB in a 32 bit integer, you could either use bit shifts and adds or just multiply that 2nd byte by 0x10101.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a 16 bit grayscale image that I want to display using WPF
I have two colors that I need to linearly interpolate to create a duotone
i have bit of code that causes an underflow: var t1, t2, delta: DWORD:
I have some scientific image data that's coming out of a detector device in
I have an application that does projection of data for my client over a
Have a bit of code ported from VB6 to VB.NET. It uses Write and
I have this bit of javascript written with jQuery 1.2.5. It's contained inside the
I'm trying to blur a depth texture by blurring & blending mipmap levels in
When solving an interview question Question A six digit number need to be found

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.