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Home/ Questions/Q 295117
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T06:25:45+00:00 2026-05-12T06:25:45+00:00

I have a 16 bit luminance value stored in two bytes, and I want

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I have a 16 bit luminance value stored in two bytes, and I want to convert that to R, G, and B values. I have two questions: how do I convert those two bytes to a short, and assuming that the hue and saturation is 0, how do I turn that short into 8 bits per component RGB values?

(The Convert class doesn’t have an option to take two bytes and output a short.)

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  1. Editorial Team
    Editorial Team
    2026-05-12T06:25:45+00:00Added an answer on May 12, 2026 at 6:25 am

    If the 16 bit value is little endian and unsigned, the 2nd byte would be the one you want to repeat 3x to create the RGB value, and you’d drop the other byte. Or if want the RGB in a 32 bit integer, you could either use bit shifts and adds or just multiply that 2nd byte by 0x10101.

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