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Home/ Questions/Q 867753
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T10:01:49+00:00 2026-05-15T10:01:49+00:00

Assuming the stream extraction won’t fail, will this if( !(stream >> token) ) throw

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Assuming the stream extraction won’t fail, will this

if( !(stream >> token) )
    throw runtime_error( "Unexpected end of recipe." );
else if( token == "something" )
    // do something
else
    throw runtime_error( "Unknown token" );

Work like this

if( !(stream >> token) )
    throw std::runtime_error( "Unexpected end of recipe." );

if( token == "something" )
    // do something
else
    throw std::runtime_error( "Unknown token" );

(stream = std::stringstream and token = std::string)
And the expected result being token contains the next … token… from the stream?
Is there a better way to handle errors? Like cerr << "error whatever" << endl; exit(); or something, or is my std::runtime_error good enough?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T10:01:50+00:00Added an answer on May 15, 2026 at 10:01 am

    Yes, the logic is exactly the same.

    And I wouldn’t ever call exit() – at least in your code the exception can be caught by some other code instead of just killing the app. You never know if you will use this code inside a larger application sometime in the future so it’s better to keep your options open 😉

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