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Editorial Team
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Asked: 2026-06-03T22:27:30+00:00

Asume that f() returns a reference to an integer ( int & f(); ),

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Asume that f() returns a reference to an integer (int & f();), f()+=5; and f()=f()+5; are different, explain how and give pesudo code for f() to illustrate this difference.

If p is an int *p, what is the difference between, these two statement in C++:

if (p!=NULL && *p !=0).... 
if (*p !=0 && p !=NULL)....
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  1. Editorial Team

    f()+=5 could be different from f()=f()+5 if f() returned a reference to a different integer at each call. This could only happen if f() read from some global variable which was different each time that it was called.

    The difference between if (p!=NULL && *p !=0) and if (*p !=0 && *p !=NULL) is that the first one checks whether p is null and then checks whether the int that p points to is 0 . The second one only checks whether the int that p points to is 0 (and performs this check twice).

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