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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T01:14:28+00:00 2026-05-14T01:14:28+00:00

At a website , I found the following code to make a jQuery plugin:

  • 0

At a website, I found the following code to make a jQuery plugin:

(function($){
  // Our code here...
})(jQuery);

I don’t understand how the code above works. What I understand is that the code executes immediately because the very last () in function(){}(). So the entire code says that is an anonymous function that is run immediately.

But I don’t understand why the wrapping needs to pass jQuery and that inside it needs $ to be passed.

From my understanding, $ is an alias to jQuery, meaning practically the same. What is the meaning of $ and jQuery here? How does the overall code work as a jQuery plugin?

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  1. Editorial Team
    Editorial Team
    2026-05-14T01:14:28+00:00Added an answer on May 14, 2026 at 1:14 am

    jQuery is the actual parameter. $ is the formal parameter. You could very well write:

    (function(ForAFewDollarsLess){
        ForAFewDollarsLess('#myId') ...
    })(jQuery);
    

    One reason is convenience – it’s short. You might be using jQuery in noConflict mode with other libraries. Maybe typing jQuery all the time is a hassle, or other plugins are following bad practices and using $ instead of jQuery. Either ways, you can use a self-calling function like the one above to solve the problem.

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