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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T10:23:17+00:00 2026-05-15T10:23:17+00:00

Basically, I have a Linked List which implements a display() function that simply loops

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Basically, I have a Linked List which implements a display()function that simply loops throught he elements and prints out their values.

I wanted to do it like this:

void List::display( std::string type )
{
    switch(type)
    {
      // Do stuff...

The compiler immediately complained. My teacher said this would be because the string is not known at compile-time, resulting in an error. That explanation sounds a little iffy, but he suggested that I use enums. So I researched it and it says that explicit string to enums doesn’t work. Something like

class List
{
    enum type 
    {
        HORIZONTAL = "inline"
        VERTICAL   = "normal"
    }

and then, I really don’t know.

The enum type is a part of the List class, as well as the function display(). This again looks like a really crappy solution. Nevertheless, I want to know if this approach is possible.

How could I set the enum in the main function at the same time I call display()? Like so

int main( void )
{
    display("normal");

Of course, easier approaches are very welcome. In general, how do I declare/pass an enum to a function, if possible?

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  1. Editorial Team
    Editorial Team
    2026-05-15T10:23:18+00:00Added an answer on May 15, 2026 at 10:23 am

    Switch, in current C++, only works with integral types. You could define your enum, switch on it, and write an auxiliary function that maps the enum to string values if needed.

    Example

    enum E { A, B };
    
    string E_to_string( E e )
    {
      switch(e)
      {
        case A: return "apple";
        case B: return "banana";
      }
    }
    
    void display( E e )
    {
      std::cout << "displaying an " << E_to_string(e) << std::endl;
      switch(e)
      {
        case A: // stuff displaying A;
        case B: // stuff displaying B;
      }
    }
    
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