Question

Basically, I’m trying to make a table where the color slightly changes for each row.

I’m going to do this by naming each even row class="even" and every odd row class="odd".

In my loop then, I need to figure out if the instance of the array is odd or even.

I can do almost do this by writing:

if (count($row)%2 == 0)  //while $row is an array from a mysql query
    {
    echo "<tr class='even'>";

if (count($row)%2 == 1)
    {
    echo "<tr class='odd'>";
    }

However writing count($row) gives me the count for the whole array, not the number of the instance which indicates where it falls in the whole array. Any ideas on how I could get the number of the instance within the array?

Thanks

Answer 1

Don’t use PHP for this. Use CSS:

tr:nth-child(even) {background: #CCC}
tr:nth-child(odd) {background: #FFF}