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Home/ Questions/Q 8643037
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T11:56:00+00:00 2026-06-12T11:56:00+00:00

b=int(1) if b == 1: b=2 c = on my thumb elif b== 2:

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b=int(1)

if b == 1:
     b=2
     c = "on my thumb"
elif b== 2:
    b=3
    c = "on my shoe"
elif b== 3:
    b=4
    c = "on my knee"
elif b== 4:
    b+1
    c = "on my door"
elif b== 5:
    b+1
    c = "on my hive"
elif b== 6:
    b+1
    c = "on my sticks"
elif b== 7:
    b+1
    c = "up in heaven"
elif b== 8:
    b+1
    c = "on my gate"
elif b== 9:
    b+1
    c = "on my spine"
else:
    c = "once again"

for r in range(10):
    print("This old man, he played one He played knick-knack " + c +" Knick-knack paddywhack, give your dog a bone This old man came rolling home")
    b+1

Relatively new to coding so I don’t really know what I am doing, but I am trying to get c to change every new time that r is printed….so that IT completes the old nursery rhyme. I am coding this in python…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T11:56:01+00:00Added an answer on June 12, 2026 at 11:56 am
    parts = ["on my thumb", "on my shoe", ...]
    numerators = ["one", "two", "three", ...]
    
    for num, part in zip(numerators, parts):
        print "This old man, he played " + num
        print "He played knick-knack " + part
        print "Knick-knack paddywhack, give your dog a bone"
        print "This old man came rolling home"
    
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