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Home/ Questions/Q 9182855
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T18:39:44+00:00 2026-06-17T18:39:44+00:00

boolean a = true boolean b = true <random code in here, booleans may

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boolean a = true    
boolean b = true

<random code in here, booleans may or may not change>

if ((!a || !b) || (!a && !b)){
    doSomethingElse();
}

This code is not working for me, what is a simple solution to this problem?

To be clear:
The if statement should work:
if at least one of the booleans is false

3 cases:

a = False b = True
a = True b = False
a = False b = False

I could do this in one long if statement, but I was just wondering if there was a simple way to implement this.

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  1. Editorial Team
    Editorial Team
    2026-06-17T18:39:45+00:00Added an answer on June 17, 2026 at 6:39 pm

    This should work for you:

    if( !a || !b ) {
      doSomething();
    }
    
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