byte b=12;
b >>= 2; // Why is this legal? why does it automatically typecasts?
b = b >> 2; // Why is this illegal if the above is legal
byte b=12; b >>= 2; // Why is this legal? why does it automatically
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byte b=12;
b >>= 2; // Why is this legal? why does it automatically typecasts?
b = b >> 2; // Why is this illegal if the above is legal
b>>=2;is same as
b = (byte) (b>> 2);15.26.2 Compound Assignment Operators