Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4611598
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T01:17:22+00:00 2026-05-22T01:17:22+00:00

Can somone explain me why the output of this small perl script is foofoo

  • 0

Can somone explain me why the output of this small perl script is “foofoo” (and not “foo”) ?

#!/usr/bin/perl -w 
my $var="a";
$var=~s/.*/foo/g;
print $var."\n";

Without the g option it works as I though it would but why is the global option matching pattern twice ?

In bash output is “foo” as expected

echo "a"|sed -e "s/.*/foo/g" 

Any explanation would be appreciated.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-22T01:17:23+00:00Added an answer on May 22, 2026 at 1:17 am

    First .* matches the a, then it matches the empty string after the a. Maybe you want .+?

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Can someone explain why this script throws an exception? $byteArray = @(1,2,3) write-Output (
When I run this code gcc gives me the output 10. Can someone explain
Can someone explain why the output of this code is true true , instead
Can someone please explain output 0 in case of first constructor without this ?
Can someone please explain me this peculiar output: #include <stdio.h> typedef struct node {
Can someone explain to me this odd thing: When in python shell I type
Can someone explain why this doesn't work? int main() { float* x; float a,
Can someone explain how New works with the With keyword in this example from
Can someone explain the reason/importance of why javascriptlint (not jslint) gives the warning inc_dec_within_stmt
Consider the following PowerShell script: function Alpha { # write-output 'Uncomment this line and

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.