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Home/ Questions/Q 7898595
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T08:28:33+00:00 2026-06-03T08:28:33+00:00

[CATransaction begin]; [CATransaction setAnimationDuration:5]; CGAffineTransform currentTransform = squareLayer.affineTransform; CGFloat angle = M_PI; squareLayer.affineTransform =

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[CATransaction begin];
            [CATransaction setAnimationDuration:5];
            CGAffineTransform currentTransform = squareLayer.affineTransform;
            CGFloat angle = M_PI;

            squareLayer.affineTransform = CGAffineTransformRotate(currentTransform, angle);
            [CATransaction commit];

and

[CATransaction begin];
            [CATransaction setAnimationDuration:5];
            CGAffineTransform currentTransform = squareLayer.affineTransform;
            CGFloat angle = (M_PI * -1);

            squareLayer.affineTransform = CGAffineTransformRotate(currentTransform, angle);
            [CATransaction commit];

I would have thought the -1 would have reversed the direction but apparently not?

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  1. Editorial Team
    Editorial Team
    2026-06-03T08:28:35+00:00Added an answer on June 3, 2026 at 8:28 am

    The angle is the same. To go full circle you need 2 * Pi, so half a circle is Pi. If you take -Pi it would end at the same point.

    EDIT: If you need to make it turn clockwise you can go slightly off -Pi. Instead of -M_PI use -3.141593 for example.

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