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Home/ Questions/Q 719557
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T05:39:22+00:00 2026-05-14T05:39:22+00:00

$ch = curl_init(url); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, test); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); curl_setopt($ch, CURLOPT_HEADER,

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$ch = curl_init("url");
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, "test"); 
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$outputArray = curl_exec($ch);

Then $outputArray will contain:

Array
(
[0] => Array
    (
        [r1] => test response
        [r2] => 4
        [r3] => 32
    )

)

So I would think PHP can see that it’s an array and treat it as such, but when I do something like

echo $outputCode[0][r_title]."\n";

it gives an error:

PHP Fatal error:  Cannot use string offset as an array in /www/test.php on line 75 

(line 75 being the echo one just above)

What am I doing wrong?

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  1. Editorial Team
    Editorial Team
    2026-05-14T05:39:22+00:00Added an answer on May 14, 2026 at 5:39 am

    The data you are getting is probably not an array, but a string containing an array structure, e.g. output by print_r(). This kind of data will not automatically be converted back into a PHP array.

    If you can control the page you are querying this from, encode the data using a method like serialize() or json_encode() and on the querying side, decode the data you get from curl using (unserialize() or json_decode()) respectively. Those functions will give you a proper PHP array.

    If you have no way to change the way the URL outputs its data, the only way I can see is (yuck!) using eval() – I can elaborate on that if need be, but it’s a really really bad idea.

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