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Home/ Questions/Q 888517
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T13:24:40+00:00 2026-05-15T13:24:40+00:00

char *a=NULL; char *s=NULL; a=(char *)calloc(1,(sizeof(char))); s=(char *)calloc(1,(sizeof(char))); a=DATA; memcpy(s,a,(strlen(a))); printf(%s,s); Can you plz

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char *a=NULL;

char *s=NULL; 

a=(char *)calloc(1,(sizeof(char))); 

s=(char *)calloc(1,(sizeof(char))); 

a="DATA"; 

memcpy(s,a,(strlen(a))); 

printf("%s",s);

Can you plz tell me why its printing DATA½½½½½½½½■ε■????How to print only DATA?? Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-15T13:24:41+00:00Added an answer on May 15, 2026 at 1:24 pm

    strlen does only count the chars without the terminator ‘\0’.
    Without this terminator printf does not know the end od the string.

    Solution:
    memcpy(s,a,(strlen(a)+1));

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