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Home/ Questions/Q 976557
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:45:54+00:00 2026-05-16T03:45:54+00:00

char *p = abc; char *q = abc; if (p == q) printf (equal);

  • 0
char *p = "abc"; 
char *q = "abc"; 

if (p == q) 
printf ("equal"); 
else 
printf ("not equal"); 

Output:
equal

Is it compiler specific, or is it defined somewhere in the standards to be as expected behaviour.

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:45:55+00:00Added an answer on May 16, 2026 at 3:45 am

    The compiler is permitted to ‘coalesce’ string literals, but is not required to.

    From 6.4.5/6 String literals:

    It is unspecified whether these arrays are distinct provided their elements have the
    appropriate values.

    In fact, the compiler could merge the following set of literals:

    char* p = "abcdef";
    char* q = "def";
    

    such that q might point ‘inside’ the string pointed to by p (ie., q == &p[3]).

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