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char p[]="abc\012\0x34";
printf("%d\n",strlen(p));
I am getting output 4. Shouldn’t it be 3 ???
Although for following i am getting 3.
char p[]="abc\0";
printf("%d\n",strlen(p));
Your string does contain four characters before the
\0, i.e.abcand\012.The latter is a valid octal escape sequence, which is 10 in decimal, i.e an ASCII linefeed character.
\0x34on the other hand isn’t valid octal – only the\0part is valid hence that’s the real end of your NUL terminated string.