Question

char * str = "Hello";

*(str+1) = '3';

cout<<str;

What I was trying to do there was to change the second character into ‘3’, turning it into H3llo

Why doesn’t it work?

Answer 1

This is undefined behaviour. You cannot change literal.

To have a pointer to literal, it should be:

  const char* str = "Hello";
//^^^^^

Then, to be able to change string, this should be, for example

char str[] = "Hello";

The other option is to allocate dynamically the memory (using malloc and free)