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Home/ Questions/Q 8704517
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T03:07:34+00:00 2026-06-13T03:07:34+00:00

class a { a(){System.out.println(A);} } class b extends a { b() { super(); System.out.println(B);}

  • 0
class a
{
a(){System.out.println("A");}
}

class b extends a
{
b()
{
super();
System.out.println("B");}
}

class c extends b
{
c(){System.out.println("c");}
}

class last
{
public static void main(String aaa[])
{
c obj = new c();
}
}

Output Comes as:

A

B

C

Shouldn’t it be:

A

A

B

C

because of super keyword

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T03:07:35+00:00Added an answer on June 13, 2026 at 3:07 am

    super(); is always there if you don’t specify explicitly. Java only adds automatic call if you don’t specify it explicitly.

    So your code

        B() {
            super();
            System.out.println("B");
        }
    

    is same as

        B() {
            System.out.println("B");
        }
    
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