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Home/ Questions/Q 3626618
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T23:47:06+00:00 2026-05-18T23:47:06+00:00

class base { public void superMethod() { System.out.println(Hello i m a super class method);

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class base
{
    public void superMethod()
    {
        System.out.println("Hello i m a super class method");
    }
}

class der extends base
{
    super.superMethod();// error identifier expected 
}

i need to call a base class method without overloading it into derive class please provide me solution for it

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  1. Editorial Team
    Editorial Team
    2026-05-18T23:47:07+00:00Added an answer on May 18, 2026 at 11:47 pm

    You don’t have to do anything apart from calling the method. You do need to be inside a instance method, constructor or a instance initializer block to do that though. You only need the super keyword if you have to make a distinction when you are overriding the method.

    class Base
    {
     public void superMethod()
     {
      System.out.println("Hello i m a super class method");
     }
    }
    class Der extends base
    {
      public void method()
      {
         superMethod();// error identifier expected 
      }
    
      public void superMethod()
      {
         super.superMethod()
      }
    }
    
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