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Home/ Questions/Q 6344351
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T20:37:17+00:00 2026-05-24T20:37:17+00:00

class Debug { internal static void Assert(bool condition) { #if DEBUG Log.Out(Asserted); #endif }

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class Debug
{
    internal static void Assert(bool condition)
    {
        #if DEBUG
        Log.Out("Asserted");
        #endif
    }
}

Will the compiler get rid of calling Assert, as it’s empty in Release builds and Optimize checkbox is checked, or there will be a calling empty method overhead?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T20:37:19+00:00Added an answer on May 24, 2026 at 8:37 pm

    No, the C# compiler won’t remove the call to Assert – it’ll just be an empty method. The JIT compiler may optimize it away in calling code; effectively that’s a special case of inlining, where the result of inlining is “nothing to execute”. However, note that the argument to Assert will still be evaluated.

    However, if you want to make the call itself conditional, a cleaner approach is to change the method to use the System.Diagnostics.Conditional attribute:

    [Conditional("DEBUG")]
    internal static void Assert(bool condition)
    {
        Log.Out("Asserted");
    }
    

    This changes the semantics: now the whole method call including argument evaluation will be removed by the C# compiler, so you could have:

    Assert(GetCountOfAllRowsInDatabase() != 0);
    

    and in debug mode it would hit the database, but in release mode it wouldn’t.

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