Question

Class test{
    function test1()
    {
        echo 'inside test1';
    }

    function test2()
    {
        echo 'test2';
    }

    function test3()
    {
        echo 'test3';
    }
}

$obj = new test;
$obj->test2();//prints test2
$obj->test3();//prints test3

Now my question is,

How can i call another function before any called function execution?
In above case, how can i auto call ‘test1’ function for every another function call,
so that i can get the output as,

test1
test2
test1
test3

currently i am getting output as

test2
test3

I cannot call ‘test1’ function in
every function definition as there may
be many functions. I need a way to
auto call a function before calling
any function of a class.

Any alternative way would also be do.

Answer 1

Your best bet is the magic method __call, see below for example:

<?php

class test {
    function __construct(){}

    private function test1(){
        echo "In test1", PHP_EOL;
    }
    private function test2(){
        echo "test2", PHP_EOL;
    }
    protected function test3(){
        return "test3" . PHP_EOL;
    }
    public function __call($method,$arguments) {
        if(method_exists($this, $method)) {
            $this->test1();
            return call_user_func_array(array($this,$method),$arguments);
        }
    }
}

$a = new test;
$a->test2();
echo $a->test3();
/*
* Output:
* In test1
* test2
* In test1
* test3
*/

Please notice that test2 and test3 are not visible in the context where they are called due to protected and private. If the methods are public the above example will fail.

test1 does not have to be declared private.

ideone.com example can be found here

Updated: Add link to ideone, add example with return value.