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Home/ Questions/Q 6677843
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T04:10:19+00:00 2026-05-26T04:10:19+00:00

class ThreadWorker { public: ThreadWorker(void); virtual ~ThreadWorker(void); static void DoSomething(); }; int main() {

  • 0
class ThreadWorker
{
public:
    ThreadWorker(void);
    virtual ~ThreadWorker(void);

    static void DoSomething();
};


int main()
{
    boost::thread thread1(ThreadWorker::DoSomething);
    boost::thread thread2(ThreadWorker::DoSomething);
    boost::thread thread3(&ThreadWorker::DoSomething);
}

I’m playing around with Boost.Thread and I notice it doesn’t seem to matter whether I use the address of operator (&) or not when passing a static member function as an argument. Does it not matter? And if not, why? Is one way more correct than the other?

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  1. Editorial Team
    Editorial Team
    2026-05-26T04:10:20+00:00Added an answer on May 26, 2026 at 4:10 am

    It effectively does not matter. Functions (free functions and static member functions, not non-static member functions) decay to function pointers. No way is more correct than the other, I happen to prefer the explicit one though.

    C++11 Standard, 4.3/1:

    An lvalue of function type T can be converted to a prvalue of type “pointer to T.” The result is a pointer to the function.

    C++11 Standard, 5.2.2/1 – Function call:

    There are two kinds of function call: ordinary function call and member function call. A static member function is an ordinary function.

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