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Home/ Questions/Q 7845609
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T17:17:24+00:00 2026-06-02T17:17:24+00:00

class ZooAnimal { public: virtual void draw(); int resolveType() {return myType;} protected: int myType;

  • 0
class ZooAnimal {
public:
    virtual void draw();
    int resolveType() {return myType;}
protected:
    int myType;
};

class Bear : public ZooAnimal {
public:
    Bear (const char *name) : myName(name), myType(1){}
    void draw(){ };
private:
    std::string myName;
};

void main()
{
   
}

When I am compiling above code I am geeting following error

error C2614: ‘Bear’ : illegal member initialization: ‘myType’ is not a base or member

Why am I getting the above error, as we can access protected member from the derived class?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T17:17:26+00:00Added an answer on June 2, 2026 at 5:17 pm

    You can’t initialize base class member in derived class initializer lists.

    You’ll need to provide a constructor to the base class:

    class ZooAnimal {
    public:
    
        ZooAnimal(int type) : myType(type) {}
    
        virtual void draw();
        int resolveType() {return myType;}
        protected:
        int myType;
    };
    

    and call it from the derived class:

    class Bear : public ZooAnimal {
    public:
                                //here//
    Bear (const char *name) : ZooAnimal(1), myName(name) {}
    
    void draw(){ };
    private:
        std::string myName;
    };
    
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