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Home/ Questions/Q 8840265
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T10:25:37+00:00 2026-06-14T10:25:37+00:00

Code example: <?php // class_database.php class database { include(class_validation.php); //this does not work $val

  • 0

Code example:

<?php // class_database.php
class database
{
include("class_validation.php"); //this does not work
$val = new validation() //this does not work
    public function login($value)
    {
if($val->validate($value))
{
//do something
}
    }
}

<?php // class_validation.php
class validation
{
    public function validate($value)
    {
if($value > 50) return true;
return false;
    }
}

How do I delegate the class validation in class database?
I do not wish to inherit (implement or extends) the class validation -> behavior in validation is not to be changed.
I just want to use the methods from validation class. Any OOP solutions?
Thanks in advance

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T10:25:38+00:00Added an answer on June 14, 2026 at 10:25 am

    You cant use include inside a class like that! Either include it at the beginning of the file ( my suggestion ) or use it one line before $val = new validation(); call.

    class_database.php:

    <?php
        include("class_validation.php");
    
        class database
        {
            public function login($value)
            {
                $val = new validation();
                if($val->validate($value))
                {
                    //do something
                }
            }
        }
    ?>
    

     
    class_validation.php:

    <?php
        class validation
        {
            public function validate($value)
            {
                if($value > 50)
                    return true;
    
                return false;
            }
        }
    ?>
    
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