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Home/ Questions/Q 7923945
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T17:29:53+00:00 2026-06-03T17:29:53+00:00

code : #import EncodeURLString.h @implementation EncodeURLString – (NSString *)urlEncodeValue:(NSString *)str { NSString *result =

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code :

#import "EncodeURLString.h"

@implementation EncodeURLString

- (NSString *)urlEncodeValue:(NSString *)str
{
    NSString *result = (NSString *)CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault, (CFStringRef)str, NULL, CFSTR("!*'\";$,#[] "), kCFStringEncodingUTF8);
    return [result autorelease];
}

- (NSString *)safeEcapeString:(NSString *)str
{
    NSString *result = [str stringByReplacingOccurrencesOfString:@":" withString:@"\\:"];
    result = [result stringByReplacingOccurrencesOfString:@";" withString:@"\\;"];
    result = [result stringByReplacingOccurrencesOfString:@"," withString:@"\\,"];
    return [result autorelease];
}

@end

this code is causing the # tag in my url to be converted into %23 is there a way that i make it stop converting the hash tags? i’ve tried removing it from here CFSTR(“!*’\”;$,#[] “) but it doesn’t work it still converts it. any help or tips would be appreciated

Thanks

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  1. Editorial Team
    Editorial Team
    2026-06-03T17:29:58+00:00Added an answer on June 3, 2026 at 5:29 pm

    Remove the hash from the legalURLCharactersToBeEscaped parameter and use CFSTR("#") for charactersToLeaveUnescaped.

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