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Home/ Questions/Q 8142711
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T12:54:03+00:00 2026-06-06T12:54:03+00:00

Code looks like that #include <cstdlib> #include <iostream> using namespace std; #define n 3;

  • 0

Code looks like that

#include <cstdlib>
#include <iostream>

using namespace std;
#define n 3;
#define m 4;

int main(int argc, char* argv[])
{
    int arr[n][m];
    bool f=true;
    for (int i=0; i<n; i++)
        for (int j=0; j<m; j++)
            cin>>arr[i][j];
    for (int i=0; i<n; i++)
        for (int j=0; j<m; j++)
            if(arr[i][j]!=a[0][j])
                f=false;
    if(f)
            cout<<"Setirler eynidir.";
    else 
        cout<<"muxtelifdir";
    system("pause");
    return 0;
}

Getting bunch of errors

enter image description here

I can’t see any problematic piece of code. Any suggestions? What am I missing?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T12:54:05+00:00Added an answer on June 6, 2026 at 12:54 pm

    Since #define is a preprocessor directive, you’re making some mistakes in your array delcaration.

    #define n 3;
    #define m 4;
    
    int arr[m][n];
    
    // This translates into 
    int arr[3;][4;];
    

    You could fix it by removing the ; after the defines:

    #define n 3
    #define m 4
    

    Or even better:

    static const size_t n = 3;
    static const size_t m = 3;
    

    As the above will give you type safety elsewhere that you may use n or m.

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