Question

code:

public class Main{
    public static void main(String[] a){
        long t=24*1000*3600;
        System.out.println(t*25);
        System.out.println(24*1000*3600*25);
    }
}

This prints :

2160000000

-2134967296

Why?

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Thanks for all the replies.

Is the only way to use L after the number?

I have tried the (long)24*1000*3600*25 but this is also negative.

Answer 1

To explain it clearly,

System.out.println(24*1000*3600*25);

In the above statement are actually int literals. To make treat them as a long literal you need to suffix those with L.

System.out.println(24L*1000L*3600L*25L);

Caveat, a small l will suffice too, but that looks like capital I or 1, sometimes. Capital I doesn’t make much sense here, but reading that as 1 can really give hard time. Furthermore, Even sufficing a single value with L will make the result long.